Integrand size = 23, antiderivative size = 36 \[ \int \frac {1}{\sqrt {2-4 x^2} \sqrt {-1-x^2}} \, dx=\frac {\sqrt {1+x^2} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {2} x\right ),-\frac {1}{2}\right )}{2 \sqrt {-1-x^2}} \]
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Time = 0.01 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {432, 430} \[ \int \frac {1}{\sqrt {2-4 x^2} \sqrt {-1-x^2}} \, dx=\frac {\sqrt {x^2+1} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {2} x\right ),-\frac {1}{2}\right )}{2 \sqrt {-x^2-1}} \]
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Rule 430
Rule 432
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {1+x^2} \int \frac {1}{\sqrt {2-4 x^2} \sqrt {1+x^2}} \, dx}{\sqrt {-1-x^2}} \\ & = \frac {\sqrt {1+x^2} F\left (\sin ^{-1}\left (\sqrt {2} x\right )|-\frac {1}{2}\right )}{2 \sqrt {-1-x^2}} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.00 \[ \int \frac {1}{\sqrt {2-4 x^2} \sqrt {-1-x^2}} \, dx=\frac {\sqrt {1+x^2} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {2} x\right ),-\frac {1}{2}\right )}{2 \sqrt {-1-x^2}} \]
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Time = 2.47 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.94
method | result | size |
default | \(\frac {i F\left (i x , i \sqrt {2}\right ) \sqrt {2}\, \sqrt {-x^{2}-1}}{2 \sqrt {x^{2}+1}}\) | \(34\) |
elliptic | \(-\frac {i \sqrt {\left (2 x^{2}-1\right ) \left (x^{2}+1\right )}\, \sqrt {x^{2}+1}\, F\left (i x , i \sqrt {2}\right )}{\sqrt {-x^{2}-1}\, \sqrt {4 x^{4}+2 x^{2}-2}}\) | \(60\) |
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none
Time = 0.07 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.44 \[ \int \frac {1}{\sqrt {2-4 x^2} \sqrt {-1-x^2}} \, dx=-\frac {1}{4} \, \sqrt {2} \sqrt {-2} F(\arcsin \left (\sqrt {2} x\right )\,|\,-\frac {1}{2}) \]
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Time = 1.98 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.22 \[ \int \frac {1}{\sqrt {2-4 x^2} \sqrt {-1-x^2}} \, dx=\frac {\sqrt {2} \left (\begin {cases} - \frac {\sqrt {2} i F\left (\operatorname {asin}{\left (\sqrt {2} x \right )}\middle | - \frac {1}{2}\right )}{2} & \text {for}\: x > - \frac {\sqrt {2}}{2} \wedge x < \frac {\sqrt {2}}{2} \end {cases}\right )}{2} \]
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\[ \int \frac {1}{\sqrt {2-4 x^2} \sqrt {-1-x^2}} \, dx=\int { \frac {1}{\sqrt {-x^{2} - 1} \sqrt {-4 \, x^{2} + 2}} \,d x } \]
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\[ \int \frac {1}{\sqrt {2-4 x^2} \sqrt {-1-x^2}} \, dx=\int { \frac {1}{\sqrt {-x^{2} - 1} \sqrt {-4 \, x^{2} + 2}} \,d x } \]
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Timed out. \[ \int \frac {1}{\sqrt {2-4 x^2} \sqrt {-1-x^2}} \, dx=\int \frac {1}{\sqrt {-x^2-1}\,\sqrt {2-4\,x^2}} \,d x \]
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